Write a c program to implement XOR functionality with out using XOR(^) operator
If you have your logic cleared with basic AND and OR gates, then this question is piece of cake for you.
Boolean equation for XOR gate is
XOR = AB´ + A´B
In C language, B´ (B ‘not’) is done by ~ operator. So now logic is pretty easy you can see in below code.
inline int Xor(int x, int y)
return ( (~x) & y ) | ( x & (~y) );
int main( )
printf("%d",Xor(1,3)); // Answer would be 2 and it run successful
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